Return-Path: william@bourbon.usc.edu Delivery-Date: Tue Sep 23 23:05:56 2008 X-Spam-Checker-Version: SpamAssassin 3.2.3 (2007-08-08) on merlot.usc.edu X-Spam-Level: X-Spam-Status: No, score=-2.3 required=5.0 tests=AWL,BAYES_00 autolearn=ham version=3.2.3 Received: from bourbon.usc.edu (bourbon.usc.edu [128.125.9.75]) by merlot.usc.edu (8.14.1/8.14.1) with ESMTP id m8O65tk0019331 for ; Tue, 23 Sep 2008 23:05:55 -0700 Received: from bourbon.usc.edu (localhost.localdomain [127.0.0.1]) by bourbon.usc.edu (8.14.2/8.14.1) with ESMTP id m8O68hME018204 for ; Tue, 23 Sep 2008 23:08:43 -0700 Message-Id: <200809240608.m8O68hME018204@bourbon.usc.edu> To: cs551@merlot.usc.edu Subject: Re: About "drop probability" Date: Tue, 23 Sep 2008 23:08:43 -0700 From: Bill Cheng SOmeone wrote: > I have a question about what exactly "customer drop probability" is when > Ctrl+C is pressed. > > e.g., mm2 -n 10, there will be 10 people totally. > At one moment, 5 people've arrived: c1 is served at s1; c2 is served at > s2; c3, c4, c5 is in the queue, then Ctrl+C is received. > > In this situation what's customer drop probability? > Is it 3/5? (5 arrived, 3 dropped) > or 8/10? (10 people, 8 dropped) > Both sounds reasonable. It's actually zero! Again, you have to report what you have measured. In your measurement, none of the customers that you have generated has been dropped! So, the drop probability (number dropped divided by number generated) is zero. -- Bill Cheng // bill.cheng@usc.edu