Return-Path: william@bourbon.usc.edu Delivery-Date: Wed Dec 10 14:33:21 2008 X-Spam-Checker-Version: SpamAssassin 3.2.3 (2007-08-08) on merlot.usc.edu X-Spam-Level: X-Spam-Status: No, score=-2.4 required=5.0 tests=AWL,BAYES_00 autolearn=ham version=3.2.3 Received: from bourbon.usc.edu (bourbon.usc.edu [128.125.9.75]) by merlot.usc.edu (8.14.1/8.14.1) with ESMTP id mBAMXLmZ015668 for ; Wed, 10 Dec 2008 14:33:21 -0800 Received: from bourbon.usc.edu (localhost.localdomain [127.0.0.1]) by bourbon.usc.edu (8.14.2/8.14.1) with ESMTP id mBAMZdab023497 for ; Wed, 10 Dec 2008 14:35:39 -0800 Message-Id: <200812102235.mBAMZdab023497@bourbon.usc.edu> To: cs551@merlot.usc.edu Subject: Re: Doubts in Weight fair Queueing example!! Date: Wed, 10 Dec 2008 14:35:39 -0800 From: Bill Cheng Someone wrote: > In the weighted queueing example, A[X3] = 1.75. So F[X3] should be 2.75 > Right?? > But in the solution, F[X3] is calculated as 3. So Is 2.75 rounded off to > 3??? No. Since the finish time of X1 is 2 (which is greater than 1.75), the finish time of X3 is 2+1=3. -- Bill Cheng // bill.cheng@usc.edu